Question

Enter your answer in the provided box. How many grams of potassium chlorate decompose to potassium chloride and 467 mL of O2 at 128°C and 725 torr? 2 KCIO3(s) → 2 KCl(s) + 3 02 (8)

Answer 1

solution . Given reaction is 2 KClO₂ (s) 2 KCl (s) + 3021 from the reaction we see that, a moles of Kulo, decomposed into 3 moles of Oz and 2 moles of Kel. That means - No. of moles of Kuo decompose = 2 x No of moles of Oz produced And No. of moles of Oz produced can be calculated as na pa given here, p2725 torr T= 128 °C 2 (2 73+ 128) K = yolk v=467mL a 0.4672 R - 62.36 2. torr.kt molt Thes n = 7254 0.467 = 0.01354 mol 62.368 Yol .. No. of moles of KClO3 decomposed a 2xool wles of keloz decomposed z 2x0.01354 -0.00903 mol .: No. of grams of KuO3 decomposed = 0.009034 122.5 =(1-11g.