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Enter your answer in the provided box. How many grams of solute are needed to make 437 mL of 8.26 x 102 M potassium sulfate?
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Answer #1


no of moles = molarity * volume in liters

molarity = 8.26*10-2 M

volume = 0.437 L

moles = 8.26*10-2 M * 0.437 L

moles = 0.0360962 moles

mass = moles * molar mass

molar mass of potassium sulfate => 174.259 g/mol

mass of solute = 0.0360962 mol * 174.259g/mol => 6.29 g

answer => 6.3 grams

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