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For the reactionM+ 3x 2Y, determine the rate of change for the reactant Xif the rate of formation for Yis 6.0x10 mol/s. Selec
Rate of chage for X- mol/s
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Answer #1

Ans :- Option (B) is the answer.

Given reaction is :

M + 3X ---------> 2Y

Overall rate = -Δ[M]/Δt = -Δ[X]/3.Δt = + Δ[Y]/2.Δt

Therefore,

The relative rate of change of X is :

-Δ[X]/3.Δt = + Δ[Y]/2.Δt

-Δ[X]/Δtreactant = 3/2 Δ[Y]/Δtproduct (Option B)

Where -ve sign shows that concentration of reactants i.e. X decreases with time.

Therefore, Option (B) is the answer

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