Question

12 Ana Cole: Attempt 1 The limiting reactant always has the smallest coefficient in the balanced equation Question 6 (0.5 points) If 0.82 mol Fe reacts with 0.24 mol O2, what is the theoretical yield, in moles, of Fe2O3? Fe +_ O _Fe2O3 ( 0.16 mol Fe2O3 0.57 mol Fe2O3 0.41 mol Fe 03 0.72 mol Fe2O3 Question 7 (0.5 points) 1 mol Sg reacts with 0.35 mol oz. what is the theoretical yield, in moles, of so, Sg + O2 → MAL SO3 0.23 mol sog

Answer 1

Answer 6 -

Given,

Moles of Fe = 0.82 mol

Moles of O2 = 0.24 mol

moles of Fe2O3 = ?

4 Fe + 3 O2 $\rightarrow$ 2 Fe2O3 [BALANCED]

Now, Divide the availabe moles by their stiochiometric coefficients, the one which is smaller is the Limiting reagent.

For Fe = 0.82 mol / 4 = 0.205 mol

For O2 = 0.24 mol /3 = 0.08 mol

So, O2 is the Limiting Reagent.

Using Stiochiometry, it can be analyzed that for 3 moles of O2 , 2 moles of Fe2O3 are produced.

So,

moles of Fe2O3 = 2/3 * moles of O2

moles of Fe2O3 = 2/3 * 0.24 mol

moles of Fe2O3 = 0.16 mol

So, 0.16 mol Fe2O3 is the correct answer

Answer 7 -

Given,

moles of S8 = 0.11 mol

moles of O2 = 0.35 mol

moles of SO3 = ?

S8 + 12 O2 $\rightarrow$ 8 SO3 [BALANCED]

Now, Divide the availabe moles by their stiochiometric coefficients, the one which is smaller is the Limiting reagent.

For S8 = 0.11 mol / 1 = 0.11 mol

For O2 = 0.35 mol /12 = 0.029 mol

So, O2 is the Limiting Reagent.

Using Stiochiometry, it can be analyzed that for 12 moles of O2 , 8 moles of SO3 are produced.

So,

moles of SO3 = 8/12 * moles of O2

moles of SO3 = 8/12 * 0.35 mol

moles of SO3 = 0.23 mol

So, 0.23 mol SO3 is the correct answer