Question

1. The LD50 of cocaine is 95.1 mg/kg. Calculate the concentration of a solution, in molarity...

1. The LD50 of cocaine is 95.1 mg/kg. Calculate the concentration of a solution, in molarity if they drank 1 liter of it.

100 g / 303.346 g/mol = 0.329 mol of cocaine.

0.329 mol/ 1 L= 0.329 M for molarity.  

Is this correct?

2. Find one other concentration unit [mass/mass (g/g) or mass/volume (g/ml) percentage, ppm or ppb] that would be toxic to a 85 kg person. Assume the density of a solution of your substance is the same as that of water. 1 mg/mL.

If 95.1 mg/kg is the LD50 of cocaine, then for an 85 kg person, A9UE2xeXpFoOAAAAAElFTkSuQmCC is lethal. This concentration in ppm, 5vytCsvVfFwAAAABJRU5ErkJggg==. I feel like I am missing something here? What do I do with the density part?

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Answer #1

For 100 gm this is correct

but for 85 kg per person

mass of solute =(95.1\times85)mg=(95.1\times85\times10-3)gm=8.08gm

moles=8.08\div303.346=0.02664mol.=0.03mol.

volume of solution=1litre=1000ml

density of solution=1gm/ml

mass of solution=1000gm

1.MOLARITY= moles\divvolume of solution in litre=0.03\div1=0.03M

2. %(mass\divmass)=(mass of solute\divmass of solution)\times100=(8.08\times100)\div1000=0.8

%(mass\divvolume)=(mass of solute\divvolume of solution)\times100=(8.08\times100)\div1000=0.8

ppm=(mass of solute\divmass of solution)\times106= (8.08\times106)\div1000=8080ppm.(approx)

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