7. The p-fluorobenzoic acid (C6FH5CO2H) has a pka = 4.14 a) Compute the Ka value for...
Need help on questions 1-3 Henderson-Hasselbalch: pH=pka + Log( [base]/(acid] ) 1. The value of Ka of nitrous acid (HNO2) is 4.6 x 104 M. Calculate the pH and the concentration of [H3O+] in a 0.02M aqueous solution of HNO2(aq). 2. Label conjugate acid-base pairs: HNO2(aq) + H2O → H30* + NO2 (aq) 3. What will happen to the reaction equilibrium if we increase the pressure in the reaction vessel? H2(g) + 12(e) → 2 HI(g)
Equations pH=-log[H3O+]; pOH= -log[OH]; pKw=14.00=pH+POH; Ka-[H3O+][A-[HA]; Kb=[BH+][OH-)[B); pKa=-log Ka; Ka. Kb=Kw Constants Ka (HS-)=1x10-19; Ka (HF) 7.2x10-4; Ka ([Al(H20).]+)7.9x10-6; Ka (H3PO4)=7.5x10-2: Ka (HPO42-) =3.6x10-13; Ka (HCI)=Huge; Ka(Na+)=tiny; Ka(Cl-)tiny; Kb(NH3)=1.8x10-5; Kw=1x10-14 1) Calculate the pH of aqueous 0.25M HCl and 0.25M HF solutions. 2) Complete the following tables for aqueous solutions of conjugate acid-base pKa pKb Kb 1.3x10-4 35 3) Complete the following table for aqueous solutions DHL TH+) OH) pOH 1x102 4) Calculate the pH of aqueous 0.15M Ba(OH)2 and...
Biochemistry 4. The ionization of p-nitrophenol is shown below (pKa = 7.0): NO2 он weak acid conjugate base a. (4 points) Identify the weak acid and conjugate base. b. (4 points)At pH 7, what are the relative concentrations of ionized and un-ionized p- nitrophenol? c. (4 points)If enough concentrated hydrochloric acid is added to a solution of p-nitrophenol to lower the pH from 7 to 5, what will happen to the relative concentrations of the ionized and un-ionized forms? d....
1 a) Write the aqueous acid dissociation reactions for an acid and base dissociation reaction for a base according to the Bronsted-Lowry definition b) Determine conjugate bases of acids and acids of bases c) Write the equilibrium expression for an acid or a base aqueous dissociation d) Evaluate strength of an acid or base based on its Ka or Kb or pKa or pKb. e) Apply Kw at 25oC and at different temperatures. f) Solve for the pH of strong...
a solution is prepared by mixing 2.50 g of acetic acid (CH3CO2H, FW=60g/mol, Ka=1.75x10^(-5) with 4.70 g of sodium acetate (CH3CO2Na, FW=82g/mol) and adding water to a 500 mL volume. Note that sodium acetate yields Na+ and CH3COO-, the conjugate base of acetic acid. a.) what is the pH? b.) 15mL of 0.50 M HCl were added to the 500 mL solution, what is the pH after addituon of acid? write answer to 3 sig. figured.
Design a buffer that has a pH of 4.45 using one of the weak base/conjugate acid systems shown below. Weak Base Kb Conjugate Acid Ka pKa CH3NH2 4.2×10-4 CH3NH3+ 2.4×10-11 10.62 C6H15O3N 5.9×10-7 C6H15O3NH+ 1.7×10-8 7.77 C5H5N 1.5×10-9 C5H5NH+ 6.7×10-6 5.17 How many grams of the chloride salt of the conjugate acid must be combined with how many grams of the weak base, to produce 1.00 L of a buffer that is 1.00 M in the weak base? grams chloride...
Question 39 1 pts A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A) and the conjugate acid of the base (B-H the pKa of HA was 4.8 and the pKa of BH* (i.e., the pKabH of B) was 9.4, what would be the value of the equilibrium constant for the above reaction to the nearest ones? Obviously, by expressing the answer to the nearest ones, we are using too many...
An organic acid has pKa = 8.95. What is its Ka value? Where does the acid fit in Table 16.2?Table 16.2 Ionization Constants for Some Acids and Their Conjugate Bases at 25°C?
The original given concentration was 25.0mL of 0.100 M HCO2H (formic acid Ka= 1.8x10^-4) with 0.100 M of NaOH. f) pH after adding 25.0 mL NaOH (Equivalence point). At this point 0.00250" ist 00250 mol of OH have been added, and therefore all the acid (HCO2H) has been converted into its conjugale the table below. 25.0 mL x L/1000 mL = 0.025 L 0.025 L x 0.1 mol/L = 0.0025 mol of NaOH added n converted into its conjugate base...
pKa value of formic acid is 3.74. calculate pH of a 0.25M solution of HCOONa the conjugate base of formic acid. Assume the coefficient are equal to 1?