Question

Balancing Chemical Equations (5.0 pts) 1) CH CH + Ca(OH)2 - CHCI + CaCl + H20 2(NH4)2Cr40. - N2 + Cros + H2O 3) 12HCIO4 + P400 H3PO4 + CIO 4) FeCl3 + AgNO3 - Fe(NO3)2 + Aga 5) FeSO4)3 + BaCl2 - F.Ch + BaSO4 Problem solving: (20.0 pts) 1. Consider the combustion of amyl alcohol, CH,OH. (10.0 pts) 2CSHOH + 150, 1000 + 12H:0 a) How many mol of O, is needed for the combustion of 1.0 mol of amyl alcohol? Show all b) How many mol of H is formed for each mol of consumed Show all work c) How many grams (gl of CO2 are produced for each mol of my alcohol burned Show all work d) How many grams (g) of CO2 are produced for each gram of amyl alcohol burned Show all work 2. The equation for the preparation of phosphorus in an electric furnaceis (10.0pts) 2CaPO4)2 + 6SiO; + 10C 6 CESO+ 1000 + P Determine: (Show all work to cach question.) a) The number of mol of phosphorus formed for each mol of CaPO 2 used b) The number of grams of phosphorus formed per mol of Cay(PO2 used. c) The number of grams of phosphorus formed per gram of Ca (Oule used d) The number of mol of cach SiO, and required per mol of Cas (Pulsused

Answer 1

The balanced equations are-

|| 1.2C2 H2 Clyt ca Cou), = 2C2 HCl3 + CaCl2 + 2420 2. (artt 4)2 CH2O4 = N2 + C-1203 +4 20 B. 12H4104 + P4 Qio — 4H3 Poy + 6 C12C14 4. Fedz + 2 AgNO3 Fe(NO3)2 + 2Agel 5. Fez (504), +3 Balla = 2 FeCl3 + 3 Basoy

LP n I 2C5H10H + 150, 710002+ 12H2O a). From the balanced chemical equation, using the stoichoimetoies, we know that 15 moles of o, is required for combustion of A J = 2 moles of amyl alcohol, :. For I mol of amyl alcohol, we would tequiste = 15/2 = 7.5 miles 02. b). From the stoichiometries, we get, ! 15 moles o consumed to get = 12 moles H20 YY ami Comsu tosimed is moles= 0.8 moles Heo is formed for each mol on. d). From equation, wegel, fom Irmel.comy/ alcohol, we get 5 moles of co2 (10) . Amount of cop produced a smalx 4401 g monow produced z = 220.059.

d) from ② , we save, ! i mol amyl alcohol-boroduce = 220.05g con. Now, Imol amyl alcohola 8-158; - Molar Man of . Leo HILOH = 88.159 m OM COC ::88:15g amyl alcohol will produce = 220.05g lg " " " 2 20:05g.com CO2. 88.15 = 2.49 2.2.59 nce som 2.2cas (pou), +6 SiO2 +10C-6 Ca Si Og +1000+P4 a) From balanced equation, 2 moles cas (pou) 2 gives - Imol Py in u 42 = 05 mol P4. b) From @, we get, 0.5 mol P4 = Imel Cos rey), Now, Molar man of Phosphorus (fy)2 4x atomig men all w Now, Molar man J 24X3121 24X312124 g/mol. ...0.5 volPqe os motx 1248 = 629 P4.

mas 0%. Moler mom of cas (pou), 9.40:08) + (2.91) + (8.16) = 310-24 g/mol From ② , we gel, I mol caz (PO4)2 = 310:24g caj(Poud, gives = 62g Py - Ig" 1 = 62 g Pu MO 310:24 = 0.199 g py ~0.2g P4- d). From the balanced equation, la mol cas (poyla ² 6 mol SiO2 = 10 mol c. 15.1 mol 1 = 2 =3 u 210-5. u Hence, 3 moles Sion & 5 moles c are requised por mol of Cag (Poy) 2