Question

9. HCl + Ca(OH)2 + H2O + CaCl2 a. When starting with 4.0 mol HCl, how many grams of CaCl2 will be made? (show work for full credit) b. When starting with 4.0 mol HCl, how many grams of HCl will be consumed? (show work for full credit) 10. If 2.6 moles of gas is in a sealed container with a volume of 22 liters and at a temperature of 400 K, what is the pressure inside the container in atmospheres? (show work for full credit) 11. If four moles of a gas at a pressure of 4.1 atmospheres have a volume of 109 liters, what is the temperature in kelvin? (show work for full credit) 12. A toy balloon filled with air has an internal pressure of 1.18 atm and a volume of 0.50 L. If I take the balloon to the bottom of the ocean where the pressure is 87 atmospheres, what will the new volume of the balloon be? How many moles of gas does the balloon hold? (Assume T = 285 K) (show work for full credit)

Answer 1

9. Helt CaCOHla hot cacha la) The balanced chemical equation for the above is, 2HCl + CaCOH)2 - 1; 24.0 + Cacles [2 moles] [Imole] [2moles] [Imole] ! ! 2moles of Hcl when it reacts with Imide Cacol), it produces 1 mole cacl as product along with 2 moles of Ho. e moles Hel - Produces 1 mole cach. 4 moles Hel - Produces a .: Number of moles of Cadg that can be produced [C4motes) a mole) 7 [ 2 moles) ( a 2 moles. * Molecular mass of cacla = I CAtomicmass of ca) +2 (Atomic mass of ci). se =1(40) + 2(35.5)] = (40+71) = 111 amu :. Molar mass of Cada = 111 g/mol This means I mole cacla = 111 grams 2.2 moles of cacla = 2(111) grams = 222 grams The amount of cacy that can be produced = 222 grams (b) From the givers number moles of Hel = 4.0 moles. (the amount o Hd) = (Number of moles) * (molar mass of Hc) Molecular mass of Hel= (Atomic mass of H) + (Atomic mated = (1+ 35.5) = 36.5 amu - Molar mass = 36.5g/mole * The amount of itd in grams= (4.0 mol)x(36.5 g/mol) = 146 grams :- Amount of Hul (in grams) = 146 grams.

10. Number of moles of gas (n) = 2.6 moles Volume of the gas (V) - 22 liters (ov) 22 L Temperature of gas (T) = 400K. Let , Pressure of gas is (P) = ? Assume that the given gas is an ideal gas. According to ideal gas equations, PV= nRT Re Universal Gas Constant. AR0.0821 Liatm.mortky - Pressure (P) = CNRT) - (2.6)mál. 0.0821 Katm.moitat) (400x3) 224 = [(26)(0.0921X400)) atm = 3.88 atm. L 22 .. The pressure of given gas (P) = 3.88 atm