Number of moles of HCl = 78.3 g / 36.4609 g/mol = 2.15 mole
From the balanced equation we can say that
2 mole of HCl produces 1 mole of CaCl2 so
2.15 mole of HCl will produce
= 2.15 mole of HCl *(1 mole of CaCl2 / 2 mole of HCl0
= 1.08 mole of CaCl2
mass of 1 mole of CaCl2 = 110.98 g so
the mass of 1.08 mole of CaCl2 = 120 g
Therefore, the mass of CaCl2 produced would be 120 g
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