Question

For the reaction 2 HCl + Ca(OH), CaCl2 + 2H2O how many grams of calcium chloride, CaCl2, are produced from 78.3 g of hydrochl
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Answer #1

Number of moles of HCl = 78.3 g / 36.4609 g/mol = 2.15 mole

From the balanced equation we can say that

2 mole of HCl produces 1 mole of CaCl2 so

2.15 mole of HCl will produce

= 2.15 mole of HCl *(1 mole of CaCl2 / 2 mole of HCl0

= 1.08 mole of CaCl2

mass of 1 mole of CaCl2 = 110.98 g so

the mass of 1.08 mole of CaCl2 = 120 g

Therefore, the mass of CaCl2 produced would be 120 g

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