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Potassium chlorate decomposes in the following manner: 2 KCIO3 (s) → 2 KCl(s) + 3 O2...
For the reaction, 2 KCIO3(s) — 302(g) + 2 KCl(s), how many moles of potassium chloride can theoretically form when exactly 1 mol of potassium chlorate decomposes? o 1 0 N 3 4 For the reaction, 2 KCIO3(s) + 302(g) + 2 KCl(s), how many moles of potassium chloride can theoretically form when exactly 2 mol of potassium chlorate decomposes? OO O 1 O N 3 4 For the reaction, 2 KCIO3(s) — 302(g) + 2 KCl(s), how many moles...
(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2) upon heating: 2KCIO3 → 2KCl + 302 Suppose 10.0g of potassium chlorate is heated to complete decomposition. What is the volume of oxygen gas produced at room temperature (25°C) and atmospheric pressure (1.00 atm)? {R = 0.0821 L'atm/K mol}
Potassium chlorate decomposes according to the following equation: 2KClO3→ 2KCl +3O2. How many moles of KCl are produced if you get 8 moles of oxygen?
are these correct ? Question 2 3 pts For the reaction, 2 KCIO3(s) + 3 02(8) + 2 KCl(s), how many moles of potassium chloride can theoretically form when exactly 2 mol of potassium chlorate decomposes? 0 2. 3 4 3 pts Question 3 D For the reaction, 2 KCIO(s) - 302(8) + 2 KCl(s), how many moles of potassium chloride can theoretically form when exactly 4 mol of potassium chlorate decomposes? 0 1 2
24. Potassium chlorate (KCIO3) was heated to give oxygen. 2KCIO3 (s) - 2KCI (s) + 202 (g) A volume of 550mL of gas was collected over water at 21°C and an atmospheric pressure of 743 Torr. The vapor pressure of water at 21°C is 19 Torr. How many moles of oxygen were collected?
Question 4 Given the decomposition reaction of KCIO3(s), 2 KCIO3(s) 2 KCl(s) + 3 O2(g) If 46.5 L of oxygen gas (O2) are produced at 208 °C and 760 torr, answer all three parts below. 1) The number of moles of O2(g) produced is Select 1 (Select) 2) The number of moles of KCIO3(s) required 895 mol nt of O2(g) as 2070 mol stated in the problem is [Select 1 2.72 mol 1.18 mol 2) The grams of KCIO3(s) required...
Question 4 1 pts Given the decomposition reaction of KClO3(s), 2 KCIO3(s) 2 KCl(s) + 3 O2(8) If 19.6 L of oxygen gas (O2) are produced at 198 °C and 760 torr, answer all three parts below. 1) The number of moles of O2(g) produced → [Select ] 1.21 mol 385 mol 2) The number of moles of KCIO3(s) require 0.507 mol 917 mol problem is Select] 2(g) as stated in the 2) The grams of KCIO3(s) required to produced...
How many grams of potassium chlorate decompose to potassium chloride and 456 mL of O2 at 128°C and 777 torr? 2 KCIO3(s)2 KCI(s) +3 02 (g) g
< Question 31 of 36 > When heated, KC10, decomposes into KCl and 02. 2 KCIO3 - 2 KCl + 302 If this reaction produced 96.1 g KCl, how many grams of O, were produced? mass: g 02 about us careers privacy policy terms of use contact us help
Solid potassium chlorate (KClO3) decomposes into potassium chloride and oxygen gas when heated. How many moles of oxygen form when 55.3 g completely decomposes? 0.338 mol 0.677 mol 0.451 mol 83.0 mol