Potassium chlorate decomposes according to the following equation: 2KClO3→ 2KCl +3O2. How many moles of KCl are produced if you get 8 moles of oxygen?
Potassium chlorate decomposes according to the following equation: 2KClO3→ 2KCl +3O2. How many moles of KCl...
postassium chlorate KClO3 decomposes according to the reaction 2KClO3 -> 2KCl +3O2 if the rate of decomposition of KClO3 at a certain time is determined to be 2.8 x 10 ^-2 mol s-1 what is the rate of formation of KCl at the same time
Given the following balanced equation: 2KClO3(s) --> 2KCl(s) + 3O2(g) How many grams of potassium chloride are produced if 25 g of potassium chlorate decompose?
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 83.4 g KCl, how many grams of O2 were produced? mass: g O2
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 82.0 g KCl, how many grams of O2 were produced? mass: g O2
When heated, KClO3 decomposes into KC and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 46.4 g KCl, how many grams of O2 were produced?
Balanced equation: 2KClO3 ---> 2KCl + 3O2 Convert moles of KClO3 ( .0078367347 moles) to moles of KCl
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 48.8 g KClO3(s).
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 98.6 g KClO3(s). mass:
Potassium chlorate decomposes in the following manner: 2 KCIO3 (s) → 2 KCl(s) + 3 O2 (s) If you start with 3.00 g of potassium chlorate, how many moles of oxygen will be produced? (first blank is a number, the next the unit) Assuming a temperature of 24.0°C and a pressure of 0.982 atm, how many liters of gas are produced? (first blank is a number the next the unit) Question 17 (6 points) A sample of 3.30 grams of...
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s) . The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 70.4 g KClO3(s) STRATEGY: Convert the mass of KClO3 to moles. Convert the number of moles of KClO3 to the number of moles of O2 . Convert the number of moles of O2 to grams. Step 1: 70.4 g KClO3 is equal to 0.574 mol KClO3...