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If 4.21x10^-3 moles of Ca^2+ react with exces PO4^3- to form calcium phosphate, how many moles...

If 4.21x10^-3 moles of Ca^2+ react with exces PO4^3- to form calcium phosphate, how many moles of the solid can form?

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Answer #1

ca. (PO4) = 3 cate 205 - 4.21x10 excess 3 moles of cat2 gué Ione) mole moles to reacts with 2 indes of Pous of solid callium

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