Mass of AlCl3 = 12.5 g
Volume of the solution = 400 ml
Molar mass of AlCl3 = 133.34 g/mol
Concentration of AlCl3 = 12.5 g x 1000ml / (400 ml x 133.34 g/mol) = 0.234 M
Each AlCl3 will release 3 Cl- ions.
Concentration of Cl- ions = 0.234 M x 3 = 0.703 M
Hence Concentration of Cl- ions is 0.703 M
Option D is correct answer
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