A 3.0 [V] battery powers a flashlight bulb that has a resistance
of 6.0 [O]. How much charge moves through the battery in 10
[min]?
Voltage V=3.0 V
Resistance R=6.0 Ohm
Current I=V/R
=3/6
=0.5 A
Current =charge flow/time
Charge Flow=current*time
=0.5*10*60(As 10 minutes is 10*60 seconds)
=300 C
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