When is using the Henderson-Hasselbalch equation not appropriate for solving for pH? Why?
In case of strong acid or strong base Henderson-Hasselbalch equation fails to determine the accurate value.
Because it assumes that the concentration of acids and its conjugate base at chemical equilibrium will remain the same as formal concentration. ( Binding of proton to the base neglected in this case)
Since this does not consider the self dissociation undergone by water, it fails to offer accurate pH for extremely dilute buffer.
If you have any questions please comment
If you satisfied with the solution please rate it thanks...
When is using the Henderson-Hasselbalch equation not appropriate for solving for pH? Why?
Using the Henderson-Hasselbalch equation, calculate the pH when 0.5 mole of sodium hydroxide is added to 1 mole of acetic acid. (pKa of acetic acid is 4.76).
1. Calculation: Using the Henderson-Hasselbalch equation, explain mathematically why a solution is at a pH below the pKa for an acid that more than 50% of the molecules have the proton on (not off). 2. Calculation: If you have a pH of 5.5 for a weak acid with a pKa of 4.76, then is there more A- or more HA in the solution? Explain why in words using your knowledge of positive or negative log numbers.
12. Using the Henderson-Hasselbalch equation, prove (mathematically and chemically) why pH equals pkat half-way to the equivalence point of the reaction. (6 pts) 13. You have a buffer that contains acetic acid and sodium acetate. Write the complete and balanced chemical reaction for what happens when sodium hydroxide is added to the buffer. Write a complete and balanced chemical reaction for what happens when hydrochloric acid is added to the buffer. (8 pts)
1. (3) Using the Henderson-Hasselbalch Equation, calculate the pH of a buffer solution that is 0.065 M in benzoic acid (HC2H5O2) and 0.125 M is sodium benzoate (NaC7H5O2). For benzoic acid, Ka = 6.5 x 105.
According to the Henderson–Hasselbalch equation, when the pH of a solution of histidine is 1.85, what is the ratio of the carboxylic acid form of the molecule to its conjugate base (the carboxylate form)? [For practice, either use Marvin Sketch or a piece of paper to draw the acid and conjugate base.] 1 or 4?
using your pH at half equivalence for acetic acid and ammonia and considering the Henderson-Hasselbalch equation, calculate their Ka and Kb values. Compare with the accepted values and explain sources of error.
The pH of a buffer is calculated by using the Henderson-Hasselbalch equation: pH=pKa +log[Base]/[Acid] Part A: What is the pH of a buffer prepared by adding 0.809mol of the weak acid HA to 0.406mol of NaA in 2.00 L of solution? The dissociation constant Ka of HA is 5.66
Topic: pH and Ka Value
Note:
y-intercept = 8.46
Henderson-Hasselbalch equation : pH = pKa +
log[A-/HA]
Literature value of pKa = 9.245
Question: Use Henderson-Hasselbalch equation
and y-intercept to determine the Ka
value for the acid in the conjugate pair (NH3
and NH4Cl). Show your work.
Use the Henderson-Hasselbalch equation to calculate the pH of each solution: a solution that is 0.190 M in CH3NH2 and 0.130 M in CH3NH3Br Express your answer using two decimal places.
Henderson-Hasselbalch equation explain the variables and constants. pH=pKa+log[A-]/[HA]