For a given reaction, the rate constant, k, was determined at different temperatures. To obtain a...
For a given reaction, the rate constant, k, was determined at different temperatures. To obtain a linear graph, one should plot:
k vs. time
ln k vs. 1/T
ln k vs. ln [A]
k vs. 1/T
ln k vs. time
ln k vs [A]
1/T vs 1/[A]
[A] vs T
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For a given reaction, the rate constant, k, was determined at
different temperatures. To obtain a...
A chemical reaction was conducted at several different temperatures (measured in K) and the equilibrium constant...
A chemical reaction was conducted at several different temperatures (measured in K) and the equilibrium constant was measured at each one. Plotting the data on a graph with ln K on the y-axis and 1/T on the x-axis gives a linear plot with slope = -4594.6 and y-intercept = 13.6. What is ΔrH° (in kJ mol-1) and ΔrS° (in J mol-1 K-1)?
A chemical reaction was conducted at varying temperatures so that the equilibrium constant, K was determined...
A chemical reaction was conducted at varying temperatures so that the equilibrium constant, K was determined at each. Thereafter it was assumed that the reaction enthalpy, DeltarxnH° was independent of temperature and a graph of 1/T (in Kelvin) vs. ln K was plotted yielding a straight line with a slope of –1586.33. What was the resulting DeltarxnH° value and was it an exothermic reaction
The reaction A ---> products was studied at a series of different temperatures. A plot of...
The reaction A ---> products was studied at a series of different temperatures. A plot of ln(k) vs. 1/T gave a straight line relationship with a slope of -882 and a y-intercept of -0.649. Additionally, a study of the concentration of A with respect to time showed that only a plot of 1/[A] vs. time gave a straight line relationship. What is the initial rate of this reaction when [A] = 0.45 at 283 K? rate (Ms-1) = _______
The rate law of a reaction is rate =k[X]³. The units of the rate constant are
1)The rate law of a reaction is rate =k[X]³. The units of the rate constant areL mol-1 s-1mol² L-2 s-1mol L-1S-2L² mol-2 s-1mol L-1S-12)Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate =k[X]³[Y]²[Z]⁰The rate of reaction will increase by a factor of136803)What data should be plotted to show that experimental concentration data fits a first-order reaction?1 / [reactant] vs. time[reactant] vs. timeln (k) vs. Ealn (k) vs. 1 / Tln [...
In a chemistry experiment that measures the kinetics of reaction at different temperatures, the activation energy...
In a chemistry experiment that measures the kinetics of reaction at different temperatures, the activation energy of the reaction can be measured by finding the slope of the line in a ln k vs. 1/T plot. The following data are gathered from this kinetics experiment: ln k 1/T (K-1) -5.5886697 0.00339156 -4.8600624 0.00326318 -3.5719857 0.00313725 Construct a scatterplot of the ln k versus 1/T and fit a least-square regression line using the graph paper below. Compute the correlation coefficient between...
Most of the time, the rate of a reaction depends on the concentration of the reactant....
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
A student determined the value of K for the reaction 2 H2 (g) + O2 (g)...
A student determined the value of K for the reaction 2 H2 (g) + O2 (g) → 2 H2O (g) at several different temperatures. The value for ∆S can be determined from: the slope of the curve at 25ºC from a plot of ln K versus T. the y-intercept of the line resulting from a plot of ln K versus T. the y-intercept of the line resulting from a plot of ln K versus (1/T). the slope of the line...
A student determined the value of K for the reaction 2 H2 (g) + O2 (g)...
A student determined the value of K for the reaction 2 H2 (g) + O2 (g) → 2 H2O (g) at several different temperatures. The value for ∆S can be determined from: the slope of the curve at 25ºC from a plot of ln K versus T. the y-intercept of the line resulting from a plot of ln K versus T. the y-intercept of the line resulting from a plot of ln K versus (1/T). the slope of the line...
5 What are the units of the rate constant (k) for first, second, or zero order reaction? Show how you determined the...
5 What are the units of the rate constant (k) for first, second, or zero order reaction? Show how you determined the units of each rate constant. >SO2 + Cla: 6. The following data were obtained at 320°C for the reaction of: SO Cla 0.00 4.00 3,00 2.00 Time, hour 1.00 0.874 [SO Cl), M 0.946 1.024 1,200 1.109 Graph: (a) In [SO Cl2] vs. time Label and attach the graphs to the worksheet. If using Excel, provide the equation...
The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 35...
The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 35 × 10⁻⁴ s⁻¹ at 322 K, what is the rate constant at 273 K? An experimental plot of ln(k) vs. 1/T is obtained in lab for a reaction. The slope of the best-fit line for the graph is -3090 K. What is the value of the activation energy for the reaction in kJ/mol?
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
5 What are the units of the rate constant (k) for first, second, or zero order reaction? Show how you determined the units of each rate constant. >SO2 + Cla: 6. The following data were obtained at 320°C for the reaction of: SO Cla 0.00 4.00 3,00 2.00 Time, hour 1.00 0.874 [SO Cl), M 0.946 1.024 1,200 1.109 Graph: (a) In [SO Cl2] vs. time Label and attach the graphs to the worksheet. If using Excel, provide the equation...
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