Question

Net Ionic equation for NH_4Cl and H_2O

Observed pH Net ionic equation for NHCl and H20 Chemical Equation: Nhực! (aq) + H2O(l) → HCl(aq) + NH, OH (8) Full lonic Equation: Net lonic Equation: Net ionic equation for CH3COONa and H20 Chemical Equation: Full lonic Equation: Net lonic Equation: Net ionic equation for NaHSO4 and H20 Chemical Equation: Full lonic Equation: Net lonic Equation: 149 Page

Answer 1

Det ionic equation foro NH4Cl and H20 : Chemical equation: NH4Cl (aq) + H2O(l) + NH4OH (8) + HCl(aq) Herre Nhacrean).is asalt, strong electrolyte hence from fully solvated inb in the aqueous mediano, In the product side Huilaq) is also a strong acid,hence completely dissociates in aqueoul solution to from Ht(ag) and al-caa) imb. But H₂O (L) and NH OH (l) are weak SOLARES

electrolyte.so, they most te so, they will not exist in completes sonic form, yin molecularo undissociated from 'full sonic equation: "Ay caq) + acaq) + H2O(l) +H*(aq) 41®caq) + NH40H(e) Toget the onetimic equations, We need to eliminate the common "no in both side of the full imic equation, Net Ionic Egpation: | NHLv.) + H2O () + H+(ax) + NH4OH (*) 2. Net ironic equation foro CH3coona and H20 : Chemical Equation: CH3Coona (aq) + H20(e) → CH3coont (2) + NaOH(aq) The salt chacornacaq) and strong base Nacht (aq) are Strong electrolyte , hence exist as dissociated in Sofvated inaquéoul solution H2008) and weak achd ets cont. (e) area ceak electrolyte hence mostly exist in indiscociated molecularo forom, ... Full lonic Equation i CH?coo@caq) + Nabocam) + H20 (1) + CH3COOH(1) + Nacaq) Now, by eliminating the common Pon Natag] tost.com) qn both side of the above full ionic equations we get the netimic equation, ... Net Ionic Equations: CH3Coo- (aq) + H2010) - CH3coot (l) + OH - (aq)

19 H2ole). 3.) Netimic equation foro NaHSO4 and H20 : chemical Equation: svetlo + 110(e H280q (aq) + Naoil (az) Salt NaHS04(09), strong acid H2504 (aq) and Strong base Nacht (aq) all are strong electroly ated imic from. Onaf weak electrolyte Full Ionic Equation, Natcaq) + Husop coa) + Holy → H@caq) + Hsocaq) + Nows, by eliminating Nat caq) and Natacaq) +'oheqera) Hogcaq) ime from both side of the above full imic equation we reach to the net imic Net Imic equaitions: H2011) Hocaq) + OH(aq) equations,