Question

11. Cu + 4HCI + Na S0. CuCl2 + 2H;0 SO2 + 2Naci Note: the R in the circle is supposed to be an arrow. Copy the chemical equation on your piece of paper and answer the following: Write the oxidation numbers in each of the spaces provided above. Identify the element oxidized _ and the element reduced Identify the oxidizing agent and the reducing agent Write the half reactions and write the overall redox reaction. (14 pts)

Answer 1

Solution - Cu + 4401 + Na2SO4 G luclo + 24,0 +502 + 2Naci Now, let us write the oxidation numbers of vonioms species in the reaction one by one. I Cu → Since Cu is a metal, which is in its elemental form S therefore its O.N. = 0; нсі — We know that H has oxidation number of the ' +1+= 0 x=-17. So, O.N. of (1=-11. Na, sou + We licnow that at ions of group 1 , must have O'No = +1 : 0.No 84 Na ='+1 We also Icnow that O.N. of oxygen is -2 .: O.N. of 0 :-2 Therefore 2(+1) + x +27(-2) = 0 => x=+67 . O.N. of S = +62 Culle + We know that halogens must have oxidation number as al ... O.N. Of ci= -1 So 2+2(-1)=0 =) x = +2 ON of Cu=+2%. Scanned with CamScanner

Hoo We lenow that oxidation number of 0 =-2. .: O.N. Of H= +/- So, - We know that o.No of o = -2 . x+2(-2) = 0 => x=+4 So, 0.N. of S=+Y/ Naci → We know that oxidation number of halogens is -1 i O.N. of 11 = - so 2-1 = 0 =) deztl. .: O.N. of Nasty Finally we have Cu : + 4HCI + Na, Soy > Cully + 2420 +502 + 2 Naci Oxiclation © + - +1 +6-2 +2 - ! +-2 +4-2 +1 -1 Reduction - So, it is clear that Sulphur (s) is reduced from +6 to +4 and Copper (Cu) is oxidiced from 0 to +2° Since Copper is oxidised, it acts as a reducing agent .: Reducing agent → lu. Since Sulphur is reduced, the compound Nags0y acts as an oxidizing agent cs Scanneck'wit Ox ielizing agent - NazsOy CamScanner

Oxidation half yeaction -7. It is clear that cu gets oxidised to 64,24. This means, it gives two electrons and form Cult "escu - lu24 + 2e- a lu $47. This means, 567 Reduction half reaction It is clear that 56-t gets reduced to gains two elections and form 541 nie., 864+ 26 gut - (2) So, overall reaction Eu 867 +20 can be written as Cu2+ + 26 sut Cuts 6t Cu2+ 4547 Scanned the CamScanner