Use the data given below to calculate All for this reaction: 26(1) + H₂O → H₂O...
please help due tonight 18. Calculate AH for the reaction NO(g) Og) NO :(g) given the following information: As part of your answer, show how the equations can be added together to give the overall or net equation. 20:(g) 30O2(g) AH -427 kJ O2(g) 20(g) AH +495 kJ NO(g) Os(g) NO2(g) + O(g) AH -199 k he th
Given the data in the table below, AHxn for the reaction 4NO (g) + 6H20 (1) -→ 4NH3(g) +502 (g) is kJ. Substance AH (kJ/mol) H20 (1) 286 NO (g) 90 34 NO2 (g) HNO3(aq) NH3(g) -207 -46 O Insufficient data O-242 O +1172 O +586 O-540
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
1. Calculate the standard enthalpy of reaction for the reaction below, 3502(g) + 03(g) → 3503(g) Using only the following thermochemical data: 250(g) + O2(g) → 2502(g) AH° = -602.8 kJ 3503(g) → 350(g) + 203(9) AH° = +1485.0 kJ 202(g) → 03(9) AH° = +142.2 kJ
Use the standard reaction enthalpies given below to determine AHⓇ rxn for the following reaction: 2 NO(g) + O2(g) + 2NO2(g) AHørxn = ? Given: N2(E) + O2(g) + 2NO(g) AH®rxn = +183 kJ AHørxn = +33 kJ 1/2N2(E) + O2(g) + NO2(g) -150. kJ O-117 kJ O-333 kJ +115 kJ +238 kJ
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
3. Given the following data: C2H2 (8) +5/2O2(g) → 2CO2 (g) + H20 (1) = - 1300. KJ C(s) + O2(g) → CO2 (g) = -394 kJ H2(g) + 1/2O2(g) → H20 (1) = -286 kJ Calculate for the reaction 2C(s) + H2(g) → C2H2 (8)
Calculate AH® for the reaction using the given bond dissociation energies. CH, (g) +202(9) — CO2(g) + 2 H2O(g) Bond AH° (kJ/mol) 0-0 | 142 H-0 459 C-H 411 C=0 799 O=0 498 C-0 358 This reaction is kJ/mol AH° = O endothermic. O exothermic.
Use the Data table to calculate ∆H for the reaction below:Reactions: Change in Enthalpy (∆H)(1) C (s) + O2 (g) -> CO2(g) ∆H1 = -393.5 kJ/ mol(2) H2 (g) + 1/2 O2 (g) -> H2O (l) ∆H2 = -285.8 kJ/mol(3) 2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l) ∆H3 = -283.0 kJ/molCalculate the enthalpy change for the reaction:2 C (s) + 3 H2 (g) -> C2H6(g) ∆H = ______________kJ/mol
MAIN QUESTIO Given the following thermodynamic data calculate AS for the following reaction at 25°C and 1 atm: XeF(9) —— XeFe(s) + Fz(9) AH®: (kJ/mol) S (J/K-mol) XeF6(9) -294 300. XeF(s) -251 146 F2(g) 10 203