The nuclide 96Nb decays by a first-order process with a rate constant of 2.96 × 10–2...
The nuclide 96Nb decays by a first-order process with a rate constant of 2.96 × 10–2 h–1. How long will it take for 86.0% of the initial amount of 96Nb to be consumed?
Homework Answers
Let initial amount is A0 = 100
Then remaining amount At = 100 - 86 = 14
K * t = 2.303 * log (A0/At)
2.96*10^-2 * t = 2.303 * log (100/14)
t = 66.43 hours ...Answer
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The nuclide 96Nb decays by a first-order process with a rate
constant of 2.96 × 10–2...
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A
certain reactant disappears by a first order reaction that has a
rate constant K= 3.5x10^-3 s-1. If the initial concentration of the
reactant is 0.500 M , how long will it take for the concentration
to drop to
0.200 M ?
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A
certain reactant disappears by a first order reaction that has a
rate constant K= 3.5x10^-3 s-1. If the initial concentration of the
reactant is 0.500 M , how long will it take for the concentration
to drop to
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