Calculate the enthalpy change for the reaction CH2CH2 (g) + H2O (l)→ CH3CH2OH (l) in kJ/mole
Calculate the enthalpy change for the reaction CH2CH2 (g) + H2O (l)→ CH3CH2OH (l) in kJ/mole
A scientist measures the standard enthalpy change for the following reaction to be-55.5 kJ: C2H4)+H20(g)CH3CH2OH (g) Based on this value and the stand ard enthalpies of formation for the other substances, the standard enthalpy of formation of CH3CH2OH(g) is kJ/mol.
The standard enthalpy change for the reaction of SO3(g) with H2O(l) to yield H2SO4(aq) is ΔH∘ = -227.8 kJ .? Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO4(aq) (in kilojoules per mole). [For H2O(l),ΔH∘f = -285.8kJ/mol]. Express your answer using four significant figures.
The standard enthalpy change for the reaction of SO3 (g) with H2O(l) to yield H2SO4 (aq) is AH° = -227.8 kJ. Part A Use the following information S(s) + O2(g) +SO2(g), AH° = -296.8kJ SO2(g) + 1 O2(g) +S03 (g), AH° = -98.9kJ to calculate AH; for H2SO4(aq) (in kilojoules per mole). [For H2O(l), AH = -285.8kJ/mol]. Express your answer using four significant figures. O AXO A o ai ? AH; = Submit Request Answer Provide Feedback
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
Use Lewis structures and bond energies to calculate the enthalpy change of the following reaction: C2H4(g) + H2O(g) → CH3CH2OH(g)
calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ
A.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. N2(g) + 3H2(g) = 2NH3(g) B.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. CaCO3(s) = CaO(s) + CO2(g) C. A scientist measures the standard enthalpy change for the following reaction to be -2910.6 kJ: 2C2H6(g) + 7 O2(g) = 4CO2(g) + 6 H2O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy...
Calculate the standard enthalpy change for the reaction 2C8H18(l) + 17O2(g) →16CO(g) + 18H2O(l). Given 2C8H18(I) + 25O2(g) →16CO2(g) + 18H2O(I) ΔH°=-11,020 kJ/mol 2CO(g) + O2(g) → 2CO2(g) ΔH° = -566.0 kJ/mol 0 -6,492 kJ/mol 15,550 kJ/mol 10,450 kJ/mol -10.450 kJ/mol 6,492 kJ/mol
A scientist measures the standard enthalpy change for the following reaction to be 2853.6 kJ : 6CO2(g) + 6 H2O(l)C6H12O6 + 6 O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is ?kJ/mol.