Question

The combustion of propane is given by the following reaction. C3H8 + 5 O2 → 3...

The combustion of propane is given by the following reaction.

C3H8 + 5 O2 → 3 CO2 + 4 H2O

The enthalpy of reaction is −2202.0 kJ/mol. How much energy (in kilojoules) will be released if 23.55 grams of propane is burned. (Molar mass of propane = 44.11 g/mol).  kJ

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Answer #1

dus) Ron!) Cz Hq + 50 - 3 00 +44₂0. propane. Step 3. find males of moles mass molan mass = 23.55 g 44.11 Ilmal moles = 0.534

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