During the dehydration of 2-methylcyclohexanol what is the rate determining step for the E1 mechanism? a....
During the dehydration of 2-methylcyclohexanol what is the rate determining step for the E1 mechanism?
a. the addition of chloride
b. dissociation of the oxonium ion to form a carbocation and water
c. elimination of the beta hydrogen
d. the formation of the pi bond
Homework Answers
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During the dehydration of 2-methylcyclohexanol what is the rate
determining step for the E1 mechanism?
a....
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is...
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion. Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction. 3-methyl-2-butanol ------->an oxonium ion
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is...
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction :он H3 3 CH3 an oxonium ion 3-methyl-2-butanol Major Product Minor Product Minor Product
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism.
Acid-catalyzed dehydration of secondary and tertiary alcohols
proceeds through an E1 mechanism. The first step is the protonation
of the alcohol oxygen to form an oxonium ion. Dehydration of
3-methyl-2-butanol forms one major and two minor organic products.
Draw the structures, including hydrogen atoms, of the three organic
products of this reaction.
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is...
Acid-catalyzed dehydration of secondary and tertiary alcohols
proceeds through an E1 mechanism. The first step is the protonation
of alcohol and oxygen to form an oxonium ion.
Dehydration of 3-methyl-2-butanol forms one major and two minor
organic products. Draw the structures, including hydrogen atoms, of
the three organic products of this reaction.
The 3.) is correct that is the minor product I came up with but
I cant get the answer correct for 1.) major product? and 2.) minor
product
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is...
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction. Realize, the major product follows Zaitsev's Rule; minor products may not follow this rule. Do NOT forget to add in all HYDROGENS! Н-б-н Н-о-н) H-O-H :он 3-methyl-2-butanol an...
1. [10 pts] Consider the elimination reaction for the following alkyl halide with sodium methoxide in...
1. [10 pts] Consider the elimination reaction for the following alkyl halide with sodium methoxide in methanol (Na* OCH, CH,OH). CH NaOme MeOH CH Compound A Problem 2c Draw the major expected organic product (a) Redraw Compound A as seen in Viewpoint I below left as a Newman projection on the template provided in Problem 2a (below). Hint: Fill in missing Hs ar C2 and C3 to help you get started! (b) Rotate the C2 C3 bond to obtain the...
Some mechanism questions – another look at substitution and elimination mechanisms. 2. Some mechanism questions -...
Some mechanism questions – another look at substitution and
elimination mechanisms.
2. Some mechanism questions - another look at substitution and elimination mechanisms. Cyclohexanol is treated with hydrochloric acid. A mixture of three products form OH HCI Cl i. Which product(s) is (are) the result of s ubstitution? ii. Of the products A and B which should have a higher yield? iii. The mechanism for all three products has the same step: the formation of a carbocation. Draw the carbocation...
Question 3 2 pts The aldol reaction often involves a dehydration step to remove an alcohol...
Question 3 2 pts The aldol reaction often involves a dehydration step to remove an alcohol and form an alkene. What is the driving force of this step? The formation of water The increase of entropy during the reaction The formation of a conjugated pi system
21) Dehydration of 1-butanol with concentrated sulfuric acid at 140°C results in the formation of mainly trans-2-bu...
21) Dehydration of 1-butanol with concentrated sulfuric acid at 140°C results in the formation of mainly trans-2-butene. According to these results, which of the following conclusions might be valid? A) The reaction undergoes an E2-type elimination mechanism. B) The reaction follows a new mechanism involving the formation of a carbanion intermediate. C) The reaction undergoes an El-type elimination mechanism in conjunction with a hydride shift. D) The reaction undergoes an E2-type elimination mechanism in conjunction with a methyl shift. E)...
Complete the electron-pushing mechanism for the E1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid....
Complete the electron-pushing mechanism for the E1 reaction when
2-methylbutan-2-ol is treated with 20% sulfuric acid.
Hint: The E1 mechanism involves dissociation of the hydroxyl
group from the substrate. The acid is used to convert the hydroxyl
group to a good leaving group. Do not delete any pre-drawn
bonds/charges/lone pairs.
Complete the electron-pushing mechanism for the E1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid Map a) Use two curved arrows to show the fast b) Use a curved...
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction :он H3 3 CH3 an oxonium ion 3-methyl-2-butanol Major Product Minor Product Minor Product
Acid-catalyzed dehydration of secondary and tertiary alcohols
proceeds through an E1 mechanism. The first step is the protonation
of alcohol and oxygen to form an oxonium ion.
Dehydration of 3-methyl-2-butanol forms one major and two minor
organic products. Draw the structures, including hydrogen atoms, of
the three organic products of this reaction.
The 3.) is correct that is the minor product I came up with but
I cant get the answer correct for 1.) major product? and 2.) minor
product
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of the alcohol oxygen to form an oxonium ion Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction. Realize, the major product follows Zaitsev's Rule; minor products may not follow this rule. Do NOT forget to add in all HYDROGENS! Н-б-н Н-о-н) H-O-H :он 3-methyl-2-butanol an...
1. [10 pts] Consider the elimination reaction for the following alkyl halide with sodium methoxide in methanol (Na* OCH, CH,OH). CH NaOme MeOH CH Compound A Problem 2c Draw the major expected organic product (a) Redraw Compound A as seen in Viewpoint I below left as a Newman projection on the template provided in Problem 2a (below). Hint: Fill in missing Hs ar C2 and C3 to help you get started! (b) Rotate the C2 C3 bond to obtain the...
Some mechanism questions – another look at substitution and
elimination mechanisms.
2. Some mechanism questions - another look at substitution and elimination mechanisms. Cyclohexanol is treated with hydrochloric acid. A mixture of three products form OH HCI Cl i. Which product(s) is (are) the result of s ubstitution? ii. Of the products A and B which should have a higher yield? iii. The mechanism for all three products has the same step: the formation of a carbocation. Draw the carbocation...
Question 3 2 pts The aldol reaction often involves a dehydration step to remove an alcohol and form an alkene. What is the driving force of this step? The formation of water The increase of entropy during the reaction The formation of a conjugated pi system
21) Dehydration of 1-butanol with concentrated sulfuric acid at 140°C results in the formation of mainly trans-2-butene. According to these results, which of the following conclusions might be valid? A) The reaction undergoes an E2-type elimination mechanism. B) The reaction follows a new mechanism involving the formation of a carbanion intermediate. C) The reaction undergoes an El-type elimination mechanism in conjunction with a hydride shift. D) The reaction undergoes an E2-type elimination mechanism in conjunction with a methyl shift. E)...
Complete the electron-pushing mechanism for the E1 reaction when
2-methylbutan-2-ol is treated with 20% sulfuric acid.
Hint: The E1 mechanism involves dissociation of the hydroxyl
group from the substrate. The acid is used to convert the hydroxyl
group to a good leaving group. Do not delete any pre-drawn
bonds/charges/lone pairs.
Complete the electron-pushing mechanism for the E1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid Map a) Use two curved arrows to show the fast b) Use a curved...
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