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calculate the change in free energy as ethanol burns under standard conditions

Practice 12.6 Calculating AGPxn Using Appropriate AG Values . Using the appropriate standard free energy of formation values
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Answer #1

Balanced reaction is

CH3CH3OH(l) + 3O2(g)   \rightarrow 2CO2(g) + 3H2O(l)

Standard free energy of formation

∆G0f CH3CH3OH(l)  = -174.8 KJ / mol

∆G0f O2(g)  = 0 KJ / mol

∆G0f CO2(g)  = -394.39 KJ / mol

∆G0f H2O(l)  = -337.14 KJ / mol

we know the equation

∆G0rxn = ∑∆G0f (product) -   ∑∆G0f (reactant)

∆G0rxn = [ 2( ∆G0f CO2(g) ) + 3( ∆G0f H2O(l) ) ] - [ ( ∆G0f CH3CH3OH(l) ) + 3 ( ∆G0f O2(g) ) ]

substitute the value

∆G0rxn = [ ( 2 X (-394.39 KJ/mol)) + ( 3 X (-237.14 KJ/mol))] - [ ( -174.8KJ/mol) + ( 3 X 0KJ/mol) ]

∆G0rxn = [-1500.2 KJ/mol] - [-174.8 KJ/mol]

∆G0rxn = [-1500.2 KJ/mol] + [174.8 KJ/mol]

∆G0rxn = -1325.2 KJ

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