A 2,560 mL aqueous sample contained 5.96 g of sodium hydroxide, NaOH.
What is the pH of the solution at 25oC.
(Na = 22.98 g/mol; O=16.0 g/mol, H=1.00 g/mol)
Conversion
1000.0 mL = 1 L
Molarity = moles/Liter
Molarity of sodium hydroxide = number of moles / volme of solution inliter
number of mole = weight in gram / molecular wight
weight in gram of NaOH = 5.96 g
Molecular weight of NaOH = 40
number of mole = 5.96 / 40 = 0.149 mole
molarity = 0.149 / 2.560 = 0.0582 mole/L
pOH = -log(OH-) = -log (0.0582) = 1.24
pH = 14- P(OH) = 14 - 1.24 = 12.76
Thus pH of this solution is 12.76 at 25oC.
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