a. Oxidation state of H =+1
Oxidation state of O = - 2
Oxidation state of P =x
Now,
1 + x + 4(-2) = -1
1+x-8=-1
x= -1+7
x=+6
Thus, oxidation state of P =6
b. Oxidation state of H =+1
Oxidation state of O =x
Now,
2(1) +2(x) =0
2+2x=0
x= -2/2
x=-1
Thus, oxidation state of O =-1
c. Oxidation state of O =-2
Oxidation state of Cl =x
Now,
x+4(-2) =-1
x-8=-1
x=-1+8
x=7
Thus, Oxidation state of Cl= 7
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