Question

a. What is the mass in grams of 1.03 x 104 atoms of vanadium? grams b. How many vanadium atoms are there in 31.0 grams of vanadium? atoms

Answer 1

we know, a mole & 6.022 x 1023 atoms. - 6.022 x103 atorns - I mole Then I aton has 6.022x1023 then, 1.03810 29 arom has 1 x 1.03 x1024 mole 022x1023 mole 6.022x023 0.171x10 moles : 1.71 nioles molar mass of vanadium : 519 So, Imobe of vanadium has slg vanadium. 2) 1.71 moes of vanadium will have 51x 1.71g = 87.219. Answer:- [ 87.21 grams

6) Molar mass of vanadium = 519 - 80 519 of vanadium = 1 mole vanadium - 31-09 9 vanadium = I x 31.0 mides 57 = 0.60 moles so mole contains 6.022x10 atoms of vanadium v. ho mole contans 6.022 x 1023 x 0.60 atoms s 3.61 x 1023 atoms of vanadium Answer & [3.61 x 1023 atours
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