Calculate ∆Go for the voltaic cell shown above.
n= moles of electrons transferred
F= 96500 Coulomb (charge on one mol of electrons)
Use the units kJ in your answer.
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Calculate ∆Go for the voltaic cell shown above.
n= moles of electrons transferred
F= 96500 Coulomb...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which i...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Cd(II) and Sc(III) Cathode: Cd(II) Sc(III) Anode: Cd(II) Sc(III) Ecell 42 (b) Pb(II) and In(III) Cathode: Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: Ni(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell- Supporting Materials We were unable to transcribe this imageAGº and Eº can...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Consider the following cell reaction at 18°C: Ca(e)+Cu+ (aq) + Ca2+ (aq) + Cu() Calculate the...
Consider the following cell reaction at 18°C: Ca(e)+Cu+ (aq) + Ca2+ (aq) + Cu() Calculate the standard cell potential of this cell from the standard electrode potentials, and from this, obtain AG" for the cell reaction. Calculate AF. Use these values of AN and AG to obtain AS for the cell reaction. Ca²+ (aq) +20 + Ca() --2.76 V Cu? (g) +20 + Cu(s) - 0.84 V AH;(O.*()) -- 542.8 kJ/mol AH;(Out (as)) - 64.8 kJ/mol V AG- AH- kJ...
I am most confused on how to find n. I found the two half reactions but...
I am most confused on how to find n. I found the two half
reactions but the electrons are unequal so I need help making them
equal as well as determining what n is
The voltaic cell that uses the following reaction of iron and chromium has a standard cell potential of £ = +0.305 V at 25.0°C. 3 Fe2+ (aq) + 2 Cr (s) 3 3 Fe (s) + 2 Cr3+ (aq) Equation 9.11 Ch09: Q12 Review Calculate the...
Free-energy change, AGº, is related to cell potential, Eº, by the equation AG° = -nFE° where...
Free-energy change, AGº, is related to cell potential, Eº, by the equation AG° = -nFE° where n is the number of moles of electrons transferred and F = 96,500 C/(mol e ) is the Faraday constant. When Eº is measured in volts, AGⓇ must be in joules since 1 J =1C.V. Part A Calculate the standard free-energy change at 25°C for the following reaction: Mg(s) + Fe2+ (aq)Mg2+ (aq) + Fe(s) Express your answer to three significant figures and include...
Au ++ 3e → Au The picture above shows a set-up that could be used for...
Au ++ 3e → Au The picture above shows a set-up that could be used for electroplating. When the Olympic Games were held in Atlanta, the United States provided gold medals for the athletes. Calculate how many grams of gold would be plated out on a coin, if a current of 3.2 (Amp) is applied for 27 min to an electrolytic cell shown above. The following reaction is occurring: Au3+ + 3 e → Au MW for gold equals 1979...
a) Use the tabulated half-cell potentials to calculate AGº for the following balanced redox reaction. (F=...
a) Use the tabulated half-cell potentials to calculate AGº for the following balanced redox reaction. (F= 96,485 C/mol e) 2Li(s) + Cl2(g) → 2 Cl-(20) + 2Li *(90 E Li (ag) +_ Li(s) -3.04V Cl: (g) + 2e_2 +1.36 V Cl(aq) -8.49 x 10 sk] b. -425 kJ a. C. +324 k] d. -849 kJ | b) Name the following coordination complex: [Fe(H 20) 4F 2]F a. tetraaguadifluoroiron(II) fluoride O b.tetraaquadifluoroiron(III) fluoride c. diflugrotetrahydroiron(II) fluoride O d. difluorotetrahydrgironfluoride c) How...
A voltaic cell similar to that shown in the figure above is constructed. The electronic device shown at the top of the...
A voltaic cell similar to that shown in the figure above is constructed. The electronic device shown at the top of the figure is a volt meter. One electrode compartment consists of a cadmium strip placed in a 1.0 M Ca(NO3), solution, and the other has a copper strip placed in a 1.0 M CUSO4 solution. The overall cell reaction is: Ca(s) + Cu2+ (aq) = Cd2+(aq) + Cu(s) (a) Fill in the information necessary to complete the half reactions...
Chem 1212 Lab Report on electrochemistry Electrochemistry When electrons transfer between reaction components in a redox...
Chem 1212 Lab Report on electrochemistry
Electrochemistry When electrons transfer between reaction components in a redox reaction, we can harness the motion of the electrons to create a potential. Electrochemistry revolves around the separation of the two half-reactions in a redox reaction and establishing two different electrodes. This might involve physically separating the half-reactions or including a separator, such as a semi-permeable membrane or plastic dividers. With the reactions separated, the electrons will need to flow through the wire connecting...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Cd(II) and Sc(III) Cathode: Cd(II) Sc(III) Anode: Cd(II) Sc(III) Ecell 42 (b) Pb(II) and In(III) Cathode: Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: Ni(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell- Supporting Materials We were unable to transcribe this imageAGº and Eº can...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Consider the following cell reaction at 18°C: Ca(e)+Cu+ (aq) + Ca2+ (aq) + Cu() Calculate the standard cell potential of this cell from the standard electrode potentials, and from this, obtain AG" for the cell reaction. Calculate AF. Use these values of AN and AG to obtain AS for the cell reaction. Ca²+ (aq) +20 + Ca() --2.76 V Cu? (g) +20 + Cu(s) - 0.84 V AH;(O.*()) -- 542.8 kJ/mol AH;(Out (as)) - 64.8 kJ/mol V AG- AH- kJ...
I am most confused on how to find n. I found the two half
reactions but the electrons are unequal so I need help making them
equal as well as determining what n is
The voltaic cell that uses the following reaction of iron and chromium has a standard cell potential of £ = +0.305 V at 25.0°C. 3 Fe2+ (aq) + 2 Cr (s) 3 3 Fe (s) + 2 Cr3+ (aq) Equation 9.11 Ch09: Q12 Review Calculate the...
Free-energy change, AGº, is related to cell potential, Eº, by the equation AG° = -nFE° where n is the number of moles of electrons transferred and F = 96,500 C/(mol e ) is the Faraday constant. When Eº is measured in volts, AGⓇ must be in joules since 1 J =1C.V. Part A Calculate the standard free-energy change at 25°C for the following reaction: Mg(s) + Fe2+ (aq)Mg2+ (aq) + Fe(s) Express your answer to three significant figures and include...
Au ++ 3e → Au The picture above shows a set-up that could be used for electroplating. When the Olympic Games were held in Atlanta, the United States provided gold medals for the athletes. Calculate how many grams of gold would be plated out on a coin, if a current of 3.2 (Amp) is applied for 27 min to an electrolytic cell shown above. The following reaction is occurring: Au3+ + 3 e → Au MW for gold equals 1979...
a) Use the tabulated half-cell potentials to calculate AGº for the following balanced redox reaction. (F= 96,485 C/mol e) 2Li(s) + Cl2(g) → 2 Cl-(20) + 2Li *(90 E Li (ag) +_ Li(s) -3.04V Cl: (g) + 2e_2 +1.36 V Cl(aq) -8.49 x 10 sk] b. -425 kJ a. C. +324 k] d. -849 kJ | b) Name the following coordination complex: [Fe(H 20) 4F 2]F a. tetraaguadifluoroiron(II) fluoride O b.tetraaquadifluoroiron(III) fluoride c. diflugrotetrahydroiron(II) fluoride O d. difluorotetrahydrgironfluoride c) How...
A voltaic cell similar to that shown in the figure above is constructed. The electronic device shown at the top of the figure is a volt meter. One electrode compartment consists of a cadmium strip placed in a 1.0 M Ca(NO3), solution, and the other has a copper strip placed in a 1.0 M CUSO4 solution. The overall cell reaction is: Ca(s) + Cu2+ (aq) = Cd2+(aq) + Cu(s) (a) Fill in the information necessary to complete the half reactions...
Chem 1212 Lab Report on electrochemistry
Electrochemistry When electrons transfer between reaction components in a redox reaction, we can harness the motion of the electrons to create a potential. Electrochemistry revolves around the separation of the two half-reactions in a redox reaction and establishing two different electrodes. This might involve physically separating the half-reactions or including a separator, such as a semi-permeable membrane or plastic dividers. With the reactions separated, the electrons will need to flow through the wire connecting...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
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