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How many grams of the first reactant in each of the following chemical equations would be needed to produce 10.8 g of N, gas?
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Answer #1

WALL molar mass of N2 .=28001 I mot g/mol No of motes in 18²8g N2= 10 8 g = 0.39 mot. 1 28-01 g/mol * 4 NH3 +382 - 2N2 + 6H₂O. N₂ Hu + 2 H₂O₂ N₂ + 4760 here, I man 1 modes of Nz from I moles of Natta - 0.39 moes of Nz from 0:39 moles of Nattu Molar

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