9) 15 gm of pollutant can be in 10^-6 g or 1 million grams of soil
So, in 4540 * 10^-6 million gram of soil , amount of pollutant present can be = 15* 4540 *10^-6 g
= 15* 4540* 10^-3 mg
68.1 mg of pollutant option 2
10) for 1 kg of body weight , amount of dose is 2 mg
therfore for 145 pounds or 145*454/1000 kg = 65.3 kg , amount of dose required is 65.2*2 = 132 mg
4) Molarity = no. of moles/ volume of solution in litre
.400 M = x*1000/200
moles of HCl = .08 mole
2) 65 bags weighs 3.4 pounds
therfore, 1 bag weighs 3.4/ 65 pounds = .052 pounds
1 bas has 30 candy , i. e weight of 30 candy = .052 pound
weight of 1 candy = .052/30 = .001744
1) 3.4 pounds of weight in 65 bags
therefore 1 pound of weight will be of 65/3.4= 19.1 bag or 19 bags
1 bag has 30 candy
therfore, 19bags will have = 19*30= 574 candy
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