the answer i have entered is incorrect
Ksp = 1.0 x 10^-25
Ka =
Phosphoric acid |
H3PO4 |
7.5×10-3 |
6.2×10-8 |
3.6×10-13 |
Solution-
The balanced net ionic equation can be written as below :
Ca3(PO4)2 (s) + 2 H3O+ (aq) 3 Ca2+ (aq) + 2 HPO42- (aq) + 2 H2O (l)
Now let's find the value of K
We have
Reaction 1 : Ca3(PO4)2 (s) 3 Ca2+ (aq) + 2 PO43- (aq) : here K1 = Ksp = 1.0 x 10-25
Reaction 2 : 2 PO43- (aq) + 2 H2O (l) 2 HPO42- (aq) + 2 OH- (aq) => K2 = 7.716 x 10-4
Reaction 3 : 2 H3O+ (aq) + 2 OH- (aq) 4 H2O (l) => K3 = 1 x 1028
adding all the three reactions we get the balanced net ionic equation
K = (K1) * (K2) * (K3)
K = (1.0 * 10^-25) * (7.716 * 10^-4) * (1* 10^28)
Hence we get
K = 0.772
the answer i have entered is incorrect Ksp = 1.0 x 10^-25 Ka = Phosphoric acid...
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