Question

2. (a) Complete the Lewis structure for the molecule shown below. How many lone pairs are there? H-C-06-H (b) Give the hybridizations of the following atoms in the structure: (i) C; (ii) Ob (c) Give approximate values of the following bond angles: (i) O -C-Ob; (ii) C-O-H

Answer 1

2 aj Lewis structure BOH 2 - There are 2+2 = 4 Lone pair in Heron b) hybridisation formula = I (V+M I charge) (M) V=Valence electron wa Mono valent aton (single bond) - Charge for (-) ve = +1 Ctove = -1 n- 2 3 4 5 6 SP SP2 SP3 sp 3d Sp3d2 for is n = 1 [4+27= 3=SP2 W Ob = m = 1% [6+27= 4 = sp3 j c =SP2 ;). Ob = sp3 C ! Oa-C-ob ! C is sp2 hybridised for sp2 bond angle is I so. 1200 1200 W C- Ob-1 0 is sp3 hybridised. so for cos bond angle is Jogo u logou