Question

A solution of Ba(OH)2 is standardized with potassium acid phthalate (abbreviated KHP), KHC3H804 (M = 204 g/mol), a monoprotic acid. If 1.530 g of KHP is titrated with 34.50 mL of the Ba(OH)2 solution, what is the molarity of Ba(OH)2? Enter your answer to 3 decimal places.

Answer 1

the calculation for the problem is shown below

Hen BacoH id celicacidic and can give 204 while KHP can ginen only 1 ht. ence a moles of *HP required to neutralise 1 mole of Ba COH)g Ba coma t &*4P +2H2O + 802++ & 6+ top Moles of CHP taken aft + oH = Mass of PHP taken a 1.53q. 1. molar mass 204gimol = 0.0075 moles, As explained above, I moles of Baconda is neutralised by a moles of kup & moles of kHP neutralised by Imole of Baloog Imole of *HP neutralised la mole of Beloh). 0.0015 moles of kHP neutralised by (coco 5x %) moles of Belor) 0.00315 moles of Balon), Molanity of dolution of no of moles of Ba COHg takes . BaCOH taken for on Standardisation No tone of solution in Li 1000 mL=12 = 0.00375 . ImL=4000L 13 4:50/1000) = 0:108 M.