Question

Question 21 (4 points) Which of the following is an SN2 reaction? OCH, OH + CH3 OH – CH3 – 0 – CH3 + H2O O CH3 I + KOH – CH3 OH + KI OCH3 CH2 I + KOH – CH2 = CH2 + H2O + OCH2 = CH2 + HCI – CH3 CH, CI

how would I solve 21 and 22

Answer 1

In the SN2 reaction the incoming nudleophile otook a Substrate from the back side of its leaving group, and then learing group leares and the nucleophile Malbed. Both ah the process occure simultaneously to give product nucko- phile Substrate product Tramition state

the two CH3OH + CH ₂ OH CH3 G-CH3 + H2O it in a condensation lien elimination molecules ) reaction. So, not 512. lie. eliminstion of 120) toom CH₃ I +KOH CH3OHTKI II- THO.... .... Il Hout KI » H ' J Alie. CHIZOH + KT The reaction, occare by JN2 mechanum hence It is a 32 reaction fotobonsaltro ronda CH₂=CH2+ KI bsorrots a N Trin ham elimination reaction so not SNE. Che - Clip the ch - CH3 + 8 irodno in roamini sat thin is an addition rest Ch g reaction m ethoden creoslo.

LaNoch Beures. So, m takes place. No Ist statement is false them, 22. For the 3N2 reaction back side attack occare Only the inversion of configuration takes place peremie product obtained. So, Just statement • In the Son2 reaction there is no formation of any charged specien to, It takes place best in polar aprotic hy nos polor solvents, 50, and statement is false. • In SN2 no to formation of carbocation. We consee from the mechanime 3rd statement is talse. - In the 502 reaction the reaction eccure by a single step. and in this step both substrate and the nucleophite takes place. 50, rate =k s substrate] [nucleophile] 30, the reaction is est ender with respect to holockkone and also lst order with respect to nucleophile And the overall order in 2. :. 4th statement in false. The Sw2 reaction follows the back side attack mechanism. So, 100% inversion product obtained. 50, 5th statement is correct