Let molecular formula of compound X = CxHyOz
CxHyOz + 1/2 (2x + y/2 - 2z) O2 -------------------> xCO2 + y/2H2O ....... (A)
m.w. of compound "X" = 44
12x + y + 16z = 44 ..................................(1)
from the equation A
44 g Organic compund produces = 44x g CO2
.: 1.5 g Org. Comp. will produce
4.5 g = 1.5 x
x = 3
Similarly for water
4 g Organic compund produces = y/2 g H2O
1.5 g Org. Comp. will produce = 9y * 1.5 / 44 g H2O
2.46 = 9 * 1.5y / 44
y = 8
on putting the value of x and y in equation (1)
12 x 3 + 8 + 16z = 44
z = 0
hence in compound X oxygen is not present.
Answer :
Molecular formula of compound X = C3H8
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