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I've been trying to do this, and I keep getting the wrong answer! A 28.3 mL...

I've been trying to do this, and I keep getting the wrong answer!

A 28.3 mL sample of 0.239 M trimethylamine, (CH3)3N, is titrated with 0.328 M hydroiodic acid.

After adding 8.10 mL of hydroiodic acid, the pH is.....

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Answer #1

Molarity of (CH3)3N Volume of (CH3)3N Moles of acid or Base Moles of (CH3)3N 0.239 M 28.30 ml * (0.001 L/1.0 mL) 0.0283 L Mol

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