Homework Answers
Kw = [H3O+]*[OH-]
Since water is neutral,
[H3O+] = [OH-]
So,
Kw = [H3O+]^2
2.93*10^-15 = [H3O+]^2
[H3O+] = 5.413*10^-8 M
use:
pH = -log [H3O+]
= -log (5.413*10^-8)
= 7.27
Answer: 7.27
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