At a certain temperature, the pH of pure water is 6.00. Kw for water at this temperature is
1.0 x 10^-6
1.0 x 10^-8
1.0 x 10^-10
1.0 x 10^-12
1.0 x 10^-14
[H3O+] = 10^-pH = 1.0×10^-6 M
Now, pure water contain equal concentration of OH- and H3O+. Thus,
[OH-] = 1.0×10^-6 M
Kw = [H3O+][OH-]
= 1.0×10^-6 × 1.0×10^-6
= 1.0×10^-12 M^2
At a certain temperature, the pH of pure water is 6.00. Kw for water at this...
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