Question

Can someone help me draw these? 1. (1S)-5-(p-methylphenyl)cyclopent-2-enol 2. (Z,2R,7S)-2-hydroxy-7-methyl-3,8-dioxooct-4-enoic acid      

Can someone help me draw these?

1. (1S)-5-(p-methylphenyl)cyclopent-2-enol

2. (Z,2R,7S)-2-hydroxy-7-methyl-3,8-dioxooct-4-enoic acid      

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Answer #1

Note for assigning R/S

If last (4) priority is below the plane I.e., on dash the clockwise rotation of priority 1 2 and 3 gives R and counterclockwise rotation gives S

If last priority is above the plane I.e., on wedge then clockwise rotation of priority 1 2 and 3 gives S and counterclockwise rotation gives R configuration. That means what the configuration of a chiral carbon will be depends on where the last priority is located

P.S. priority of the atoms of chiral carbon is assigned according to CIP rule.

1. To draw The structures, the first thing well do the structures, the a 1 is to g draw the carbon skeleton The on parent caTherefore the structure would be.. OH

You don't have to mention the numbering of parent carbon chain. I mentioned it just to make you understand. Please like the answer if it helped. Thank you. :)

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Can someone help me draw these? 1. (1S)-5-(p-methylphenyl)cyclopent-2-enol 2. (Z,2R,7S)-2-hydroxy-7-methyl-3,8-dioxooct-4-enoic acid      
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