Question

1. Assume the brick gains 1.0 kJ of energy for each inch it is raised above the ground. What values of energy could the brick have using the ramp system?

________ KJ

2. Indicate a value of energy that could be gained using the step system?

________KJ

3. Which system is quantized? Which system is continuous?

Step: _______

Ramp: ______

4. Could the movement of an electron in the hydrogen atom from a higher excited state to the second energy level release energy with a wavelength of 550 nm? Explain.

Wavelength (nm) 656.3 486.1 434.1 410.2 red green blue violet

Answer 1

Here simple results from bohr model of atom has been used to answer the question in section 4

Ramp system "As brick an have to any vextical height so it can have & 13kst - - - - - - find Energy (KJ) at - trinch heigh above grond a any energy ie continous energy depending upon vertical list height soms examply at 3 inch it was have 3 kJ energy at 2.5 inch it will have 2.5 kJ energy at 1.75 inch it will have 1.75 kJ energy. store=6kJ R=4K5 Energy (kJ) Height in inch Lor 5=2KJ Li +2 Now in step System istay In step system brick boo con possible position from ground în integral multiple of 1 as shown on the figuse. Hence, it can have energy in integral moltoph of a it at height 2 inch it will have 2 kJ energy at height winch it will have u kJ energy at height 6 inch it will have 6 KJ energy. ③ Step system is quantized (ie con bave ody discrete energy) Romp system is continous (re. can have all pocable energy &

© mos wapo vayas posoape og mom hbrana wansoy let check this by using equation 1E = 1346 ev (s2 - hos) — ® LE = energy corresponding wavelength 550nm n = nth energy level now AE = he - 1240 N nm = 2.254 eV 550 nm From equation , we get 2-254 eV = 13.6 ev (a - b) 0.0842 => 01364 = l ) => 0.166 = (0-25 - 2) => 2 = 0.25 -0.166 = n² = tu. But n² t 11.876 2 as n take ody integer values om positive integer Hence, there is no excted steete from where electron con tronation to second energy level to release energy cooth coavelength of 550 m > n = 11.876 and square of integes is always