Question

CH,(9) + 2 H,S(g) = CS (9) + 4 H (9) A 2.0 L reaction container initially contained 0.10 mol CH, and 1.5 mol H2S. At equilibr
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at t=0 CHA (g) + 2 H2S (g) = CS2 (g) + 4H2(g) 0-10 mol 5 mol 0 0 Olo-R 105-22 n AR at equilibrium um Since the number of molei ke = (0.100) * (0.025 (6.023) (0-250) 0.0001 0.0625 Kc = 0.0016 1.6 X10-3 Therefore, the equilib shium constant (ka) for th

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