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1. Chapter 9: Questions and Problem 9.7 (20 points, 10 points each) (a) Given here are the solidus and liquidus temperatures
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Answer #1

i) Phase diagram of GeSi alloy.

- 1400 Liquidus - - - - - - - - Solidus Temperature (°C) Liquidus + Solidus Liquidus Temperature (°C) 7.5 % 20% Solidus 1100

ii) Firstly we need to draw a line, 20 wt % of si composition at a temperature of 1100 C.

and, then a red line (known as Tie line) is drawn where it intresects both the liquidus state and solidus state and the wt% where labelled (in the above figure)

so, the weight% of liquidus state is 7.5% and solidus state is at 26 %.

for finding the weight fraction of the alloy, lever rule is followed,

Lever states that,

"It can be used to determine the fraction of liquid and solid phases for a given binary composition and temperature that is between the liquidus and solidus line".

Ws=Wo-W1/Ws-W1

where,

Ws is the Wt% of solid = 26%

Wo is the Wt% of silicon at 1100 C = 20%

Wl is the Wt% of liquid = 7.5%

so, a tie line is drawn parallel to the x axis where it intersects both the states

for finding the weight fraction of liquidus phase above equation is followed by modifing according to the liquid region

W=Wo-Ws/WS-W1

Wl = (26-20)/(26-7.5) *100  = 32.5 %

same as follows for Solid region,

Ws = (20-7.5)/(26-7.5) *100  = 67.5 %

the total wt fraction should be equal to 100

So, Ws+Wl =100

67.5 % +32.5 % =100 %

Hence Proved.

Thank you

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