i) Phase diagram of GeSi alloy.
ii) Firstly we need to draw a line, 20 wt % of si composition at a temperature of 1100 C.
and, then a red line (known as Tie line) is drawn where it intresects both the liquidus state and solidus state and the wt% where labelled (in the above figure)
so, the weight% of liquidus state is 7.5% and solidus state is at 26 %.
for finding the weight fraction of the alloy, lever rule is followed,
Lever states that,
"It can be used to determine the fraction of liquid and solid phases for a given binary composition and temperature that is between the liquidus and solidus line".
where,
Ws is the Wt% of solid = 26%
Wo is the Wt% of silicon at 1100 C = 20%
Wl is the Wt% of liquid = 7.5%
so, a tie line is drawn parallel to the x axis where it intersects both the states
for finding the weight fraction of liquidus phase above equation is followed by modifing according to the liquid region
Wl = (26-20)/(26-7.5) *100 = 32.5 %
same as follows for Solid region,
Ws = (20-7.5)/(26-7.5) *100 = 67.5 %
the total wt fraction should be equal to 100
So, Ws+Wl =100
67.5 % +32.5 % =100 %
Hence Proved.
Thank you
1. Chapter 9: Questions and Problem 9.7 (20 points, 10 points each) (a) Given here are...