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Calculate the pH at 25°C of a 0,59 M solution of potassium butanoate (KC,H,CO2). Note that butanoic acid (HC,H,CO,) is a weak
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Answer pH = 9.3

ли: pka foy Не, н, о, и 4-8 р. ka = 10-pka 2 10 4.82 1.51 X10 Now we have conjugate base of butannic acid, that is potersium3.898 x 10-10 = x2 - x = 1.97 x Cor] 165 - Now, por = -log [on] - log to (1.97 XIES) pol= 4.70 14 – poh - .9295 - 14- 4.70 CS

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