Question

Please do the calculations and show work for the three highlight questions! Thank you :)

Exp 5: Nucleophilic Substitution imental Results Mass of starting material (triphenyl methanol) = 0.10 g Theoretical yield cylcohexanone = Mass of product (triphenyl methyl bromide) = 0.14 g Percent yield = 2,4 DNP derivative M. P. (text) = 162°C M.P of product = 150.3°C M.P. Percent Difference =

Answer 1

Solutien: Mass of the stauting matemal Ctmiphenyl methanol = 0.109. Smolare mass of tmphenyl methanol - 260.33 g/mol I molau mass of triphenyl bromide = 323.29/mol mass of the product (triphenyl bromide) formed = o.llg 260.33g of triphenyl methanel gives= 323.29 of bripherie 19 of tripheryl methamal gives = 30.2 g of temperaturen 0.0g of triphenyl methanel will give = 323.2 x 0.10 260.33 methanael - 323.2 0.10 0.10 x g of triphenyl O bromide. 12 a of triphenye = 0.1242 9 0 bromide. 0.1242 Theoretical yield of triphenye bromide = 0.12429 Experiment jield Cox mass of) of the product triphen -bromide = 0.149 Percentage yield - Experimental yield x 100 Theoretical yield = 0.14 x 100 Percentage yield = 112.72%) → As, the percentage yield is gureater than 100% , it means either the produit is not doy or the product centains Theoretical melting point of the product = 153°C (from . Pinternet) Experimental melting point of the product = 150.3°C Difference in the map = 153-150.3°C - 2.7°c mop peacent differente = 27 X100 = 1.76477 Note mop percent difference can mot be caclulated from the derivative of the product, impurities. 153 = 1.76