Question

Trimethyloxonium tetrafluoroborate reacts with methanol (CH3OH) to give dimethyl ether (CH3OCH3). Which equation, including the curved arrows, best represents the rate-determining step in the mechanism? CH3 HC=0 BFT CH3 Trimethyloxonium tetrafluoroborate CH3 -> H2C+ + A. H2CO3 CH CH, : 0 CH CH3 B. H,C0 + HCA • HỌC-0: CH3 C. HỌC-0: + HCCO HAC-0 CH, CH3 + :0 . CH CH3 + :0 - CH3 + 4. Co CH3 D. HşC–o: → HșC-0 CH,

Answer 1

D must be right answer

Methyl alcohol gives its proton to  tetrafluoroborate anion forming HBF​​​​4​​​ and CH3O​​​-

In next step methoxide anion will work as nucleophile and attack at trimethyloxonium cation forming dimethyl ether