Question

7) Calculate the reaction enthalpy for the combustion reaction of hydroxyb2-butanone (CH0, given the following energy value C
0 0
Add a comment Improve this question Transcribed image text
Answer #1

ahia Ence. Practants - E nie-t products B.E = Bond Energy Here we have- + 50=0 4H-OH + 40=c=0 H Y Y LH in ОН Bonds in product

Add a comment
Know the answer?
Add Answer to:
7) Calculate the reaction enthalpy for the combustion reaction of hydroxyb2-butanone (CH0, given the following energy...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1) For the following balanced reaction: 3H2(g) + 1 N2(g) → 2 NH3(g) a) Calculate the...

    1) For the following balanced reaction: 3H2(g) + 1 N2(g) → 2 NH3(g) a) Calculate the heat of reaction (AHRXN) using AH from Table 1 b) calculate the heat of reaction (AHRXN) using Bond Energies from Table 2 c) Is the reaction endothermic or exothermic? Explain based upon your results from part a and b. 2) Calculate the energy required in Joules to heat 275.5 g of ice at -40.0°C to water at 60.0°C. 3) For blue light with an...

  • Estimate the A Hº for the following reaction in kJ at 25°C using the table of...

    Estimate the A Hº for the following reaction in kJ at 25°C using the table of bond energies provided CH3-CH-CH, SO CH3-C-CH, below: OH 2-propanol 2-propanone Just enter a number (no units). This is an oxidation reaction converting an alcohol to a ketone (specifically nail polish remover). Ignore the compounds above and below the reaction arrow; they are the inorganic reagents needed for this acid-catalyzed reaction to proceed. Table 9.2 Average Bond Energles (kJ/mol) and Bond Lengths (pm) Bond Energy...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT