Homework Answers
8. From Boyle's law,
for a given mass of gas at constant temeprature, P1V1 = P2V2
P1 = initial pressure of oxygen gas = 1.20 atm
V1 = Initial volume of oxygen gas = 44.40 mL
P2 = final pressure of oxygen gas = 0.80 atm
V2 = final volume of oxygen gas = ?
1.20*44.40 = 0.80* V2
Therefore, final volume of the oxygen when presssure is reduced to 0.80 atm is 66.60 mL
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