Question

chem

Consider the reaction, SOzC120g) à SO2c9) + Cl219) Kc= 4.80x10 at 500k AH = -62.50 kJ/mole A.) If the reaction mixture initially contains. 0.125 M SO₂Cl2, what are the equilibrium concentrations of SO2 and Cl2 ? [S0₂ Jeq = - [CI 2 Jeq = - b. what is kc at 750K? Briefly explain why ke changed the way it did. That is, why did ko. increase/ decrease with the increase in temp? c. What is the total pressure of the system if the reaction is occuring in a 1.00L vessel?

Answer 1

Solution:- Reaction given ist SQ C2 (9) 2 SO259 +012 (9) Ke=4.80x106 C at sook AH=-62.50 kJ/mol ! Now, (9) Initial molarity of socl = 0.125m Let 'sim oq sola dissociated at Equilibrium. Soalho? SO₂ (9, & cla (g) Initi od 0.125 - - Molarity At Equilibrium 0.125-a a a we know, kes [502] [aa] S [SO2U2] where [soa 2] = 0.125-80 S5o₂]sx , & [ 2] => . We have, 4.8 x10 6 : x x x 0.125 -a or, (0.125-2) 4.80100 .x2 32. - 4.8x10^-6 (0125-) = 0 os, 32 - 006*106 + 4.3x106700 O, 22 + 4.8x10x - 0.6x16 =0 is a quadratic Equation. • we r 4.2x10" (4.8)*1092-4*1*(-0.6X166) 21 - 201 ugrob t J 23.01x012 + 2.4x10 6 or J 23.048 10-12 a = -4.8x10 " t 2

or, u: -4.8x10 t J 24 x 10-6 + 23.0441612 2 Neglecting term 23.04x102 because it is very much small with respect to 2.4x156 ..so, Eg. becomes, ge= (pbx10 1 52.48156 -4.6x156 & 1.55*103 2 2 negative terms, since conce cannot me get on neglecting be negative 23 -4.8x10-6 + 1-55X103 - 2 ov, x= (1-55 -0.0048) 210315452x703 2 on x 0.77X103 *, *= 7.7 X10 4Me & Equilibrium concentration of soa and the are [SO] eg. = 7.7x15"M leg. = 707 8 10 YM =

(6) Ks = ? At : 750k But Ke=4.8x100 At sook AH. =-62.50 kJ/mol. We have lant Hoff equation, to tenka - - Ant A ke, R l Tz TJ OT *on the it - 2 S০১ 8. 314 - 62.50103 l 8.314 L soo-7507 500 x750 / kea or enkas 7:52x Love x(250) 3754100 or en kaz za 1880 .- 3-5:01 1. Ker 375 - Taking Antiln , we get Rcg : fetelor 0.00667 - 6.67x10,3 Key OV, Ken : 6.67 x 108 xike, ; 6.67X163 x 4.0 x106 00 Key = 32.02 x 109

ic. Ke= 32.02 x 101 Here , ke decrease at a 150k 7501 As, temperature increases, ke decrease , it is due to sh=-ve values ie exothermic reactions using her chotelier principle, As temperature ineblose bea tim shift backward ('. exothermic reaction) ; So, ke deosease. (c) Assuming be ha behaviour of gases to be ideal, At sook, R=0.0821 Latm ka mall Protas? V= 1.001, and total moles a moles of Soul, & moles of so 1 & moles of Molasitys no. of moles Volume (2) moles o 50,42 :: 10.125- 7.7x109)x1=0.124 80 = 7.77154 , moles of cl2 = 7.7x107 Total moles: 0.124 + 7.7x10 +7.7 x 104 0.124 + 15:4x10">0.124 + 1.54 xin or total molds 0.12554 0.12 6 moles. Now, we know, PV = nRT - 0.126 + 0.0821 x 500 7nRT or Pq = 5.17 alm & 5 2 atu Torad preure of system is 5.2 atom. :
Please give me better rattings.

Thank you.