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Question 6 (5 points) What is the ASº if the AH° is +48.90 kJ and AG° is +19.01 kJ? Oa) -0.1003 ) Ob) +100.3) Oc) +0.1003 )
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Answer #1

∆G = ∆H - T*∆S

∆H = +48.90 kJ

∆G = +19.01kJ

T = 298 K

∆S = ?

∆G = ∆H - T*∆S

19.01 = 48.90 - 298*∆S

19.01 - 48.90 = 298 ∆S

∆S = 0.1003 kJ

∆S = 0.1003 * 10^3 J

∆S = +100.3 J ......answer

Option (b) is correct

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