find the equilibruim constant of S2. please show steps Consider the reaction for the decomposition of...
Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g)⇌2H2(g)+S2(g), Kc = 1.67×10−7 at 800∘C A 0.500 L reaction vessel initially contains 0.175 mol of H2S and 6.25×10−2 mol of H2 at 800∘C. Find the equilibrium concentration of [S2].
1. Consider the reaction for the decomposition of hydrogen disulfide: H2S(g) = 2H2(g) + S2(g) With an equilibrium constant of 1.67x10-7 (at 800 °C). If a 0.500 L reaction vessel initially contains 0.0125 moles of H2S. Find the equilibrium concentrations of the products; H2 and S2. (25 points)
Consider the reaction for the decomposition of H2S: 2H2 (g) --> 2H2 (g) + S2 (g) <-- Kc= 1.67 x 10^-7 at 800 degrees Celsius H 0.5 L reaction vessel initially contains 0.0125 mol of H2S at 800 degrees Celsius find the equilibrium concentrations of H2 and S2
Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g)⇌2H2(g)+S2(g) Kc = 1.67×10^-7 at 800∘C The reaction is carried out at the same temperature with the following initial concentrations: [H2S]=1.00×10^−4M [H2]=0.00M [S2]=0.00M Part A Find the equilibrium concentration of S2
Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g)⇌2H2(g)+S2(g), Kc = 1.67×10-7 at 800∘C The reaction is carried out at the same temperature with the following initial concentrations: [H2S]=3.20×10-4M [H2]=0.00M [S2]=0.00M Find the equilibrium concentration of S2. Express the concentration to three significant figures and include the appropriate units.
Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g) = 2H2(g) + S2(g), Kc = 1.67 x 10-7 at 800°C The reaction is carried out at the same temperature with the following initial concentrations: [H2S] [H2] [S2] 4.00 x 10-4M 0.00 M 0.00 M - Part A Find the equilibrium concentration of S2. Express the concentration to three significant figures and include the appropriate units. HA ? [S2] = Value Units
Analytical exam #3 - Fall 2019 ANSWER ALL QUESTION with full explanation and calculations for full credit. 1. Consider the reaction for the decomposition of hydrogen disulfide: H2(g) → 2H2(g) + S2(8) With an equilibrium constant of 1.67*10' (at 800 °C). If a 0.500 L reaction vessel initially contains 0.0125 moles of H2S. Find the equilibrium concentrations of the products; H2 and S2. (25 points)
Consider the reaction for the decomposition of hydrogen sulfide: 2 H2S(g) ⇌ 2 H2(g) + S2(g) A 0.300 L vessel initially contains 0.450 mol of H2S at 800oC. Find the equilibrium concentration of S2. Kc = 1.67 x 10-7 at 800oC. 1) 3.54 × 10-4 M 2) 0.00204 M 3) 0.00455 M 4) 1.94 × 10-4 M 5) 0.00551 M
what is the equlibrium concentration of S^2 Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g) = 2H2(g) + S2(g), K. = 1.67 x 10-7 at 800°C The reaction is carried out at the same temperature with the following initial concentrations: H2S] = 2.50 x 10-4M [H2] = 0.00 M [S2] = 0.00 M
1) Consider the reaction for the decomposition of H2S at 800 °C where the KC is 1.67 x 10-7. In a 0.5 L reaction vessel the initial concentration of H2S is 0.0125 mol at 800 °C. What are the equilibrium concentrations of H2, S2, and H2S? 2 H2S(g) ⇌ 2 H2(g) + S2(g) 2) At 350 °C the equilibrium pressure of the following reaction mixture is 0.105 atm. What is the Kp and KC of the for the reaction? CaCO2(s)...